(x+2)(x+2)-y^2=0

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Solution for (x+2)(x+2)-y^2=0 equation: 


Simplifying
(x + 2)(x + 2) + -1y2 = 0

Reorder the terms:
(2 + x)(x + 2) + -1y2 = 0

Reorder the terms:
(2 + x)(2 + x) + -1y2 = 0

Multiply (2 + x) * (2 + x)
(2(2 + x) + x(2 + x)) + -1y2 = 0
((2 * 2 + x * 2) + x(2 + x)) + -1y2 = 0
((4 + 2x) + x(2 + x)) + -1y2 = 0
(4 + 2x + (2 * x + x * x)) + -1y2 = 0
(4 + 2x + (2x + x2)) + -1y2 = 0

Combine like terms: 2x + 2x = 4x
(4 + 4x + x2) + -1y2 = 0

Solving
4 + 4x + x2 + -1y2 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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